Strict stationary squeezing limit for one-mode thermal diffusion

Solved ID op_71f84253f425fc7e Last edited 10 September 2026
Edit

Problem

Does every stable one-mode thermal Gaussian diffusion obey the sharp stationary squeezing bound \(\lambda_{\min}(V_\infty)>\nu/2\)? Use \(R=(q,p)^{\mathsf T}\), \([q,p]=i\), and covariance \(V_{jk}=\langle\{R_j-\langle R_j\rangle,R_k-\langle R_k\rangle\}\rangle\). Let \(G\) be any real symmetric \(2\times2\) matrix, \(\kappa>0\), and \(\nu=2\bar n+1\) with \(\bar n\geq0\). Define the drift and diffusion in Eq. (1).

\begin{equation} A=\Omega G-\frac\kappa2I_2,\qquad D=\kappa\nu I_2,\qquad \Omega=\begin{pmatrix}0&1\\-1&0\end{pmatrix}. \tag{1} \end{equation}

Assume \(A\) is Hurwitz stable: both eigenvalues have negative real part. The stationary covariance \(V_\infty\) solves Eq. (2).

\begin{equation} AV_\infty+V_\infty A^{\mathsf T}+D=0. \tag{2} \end{equation}

Sharpness means that the infimum of \(\lambda_{\min}(V_\infty)\) over stable choices of \(G\) is \(\nu/2\).

Source

This is the single-mode isotropic-diffusion form of the stationary squeezing limit in Harwood and Serafini, Eq. (15) [HS20]. Their physical setting is passive interferometric coherent feedback with rotating-wave coupling to equal-temperature Markov baths.

Progress

Reports do not certify correctness or automatically change the problem's status. Progress policy.

  • Stability implies the unique solution \(V_\infty=\int_0^\infty e^{At}D e^{A^{\mathsf T}t}\,dt\) is positive definite. Multiplying Eq. (2) by \(V_\infty^{-1}\) and taking the trace gives Eq. (3), since \(\operatorname{tr}A=-\kappa\).

    \begin{equation} \operatorname{tr}(V_\infty^{-1})=\frac2\nu,\qquad \frac1{\lambda_{\min}(V_\infty)}<\operatorname{tr}(V_\infty^{-1}). \tag{3} \end{equation}

    Equation (3) proves the strict bound directly and agrees with the published result [HS20].

  • For \(0\leq s<\kappa\), choose \(G_s=\begin{pmatrix}0&-s/2\\-s/2&0\end{pmatrix}\). The stable drift and covariance in Eq. (4) show sharpness.

    \begin{equation} \begin{aligned} A_s&=\frac12\operatorname{diag}(-\kappa-s,-\kappa+s),\\ V_\infty(s)&=\nu\operatorname{diag}\!\left(\frac\kappa{\kappa+s},\frac\kappa{\kappa-s}\right),\\ \lim_{s\uparrow\kappa}\lambda_{\min}(V_\infty(s))&=\frac\nu2. \end{aligned} \tag{4} \end{equation}

Comment

The question is completely resolved, with a peer-reviewed source and a direct verification above. The limit is an infimum approached at instability, not a stable minimum. Isotropic noise and one mode are essential hypotheses; the statement does not cover arbitrary multimode feedback or anisotropic baths.

References

[HS20]
A. Harwood and A. Serafini, “Ultimate Squeezing Through Coherent Quantum Feedback,” Physical Review Research 2, 043103 (2020).DOIarXiv

Cite this problem

Please also cite the primary sources listed under References. Cite this page for the statement, status, and stable identifier.

BibTeX

@incollection{qiqcop_op_71f84253f425fc7e,
  title = {Strict stationary squeezing limit for one-mode thermal diffusion},
  booktitle = {Quantum Information and Quantum Computation Open Problem Zoo (QIQCOP Zoo)},
  year = {2026},
  howpublished = {\url{https://qiqc-op.com/problem/op_71f84253f425fc7e/}},
  note = {Stable ID op_71f84253f425fc7e; status: Solved; accessed 2026-10-08}
}

Plain text

“Strict stationary squeezing limit for one-mode thermal diffusion,” Quantum Information and Quantum Computation Open Problem Zoo (QIQCOP Zoo), https://qiqc-op.com/problem/op_71f84253f425fc7e/, ID op_71f84253f425fc7e, accessed 2026-10-08.

Share this problem

Permanent link

Identifiers

op_71f84253f425fc7e
01M26K8Q9WAW3Q9PKGYVXHHX0C